A 2.58 g particle is moving at 2.51 m/s toward a stationary 6.53 g particle. With what speed does the heavier particle approach the center of mass of the two particles

Given that,

Mass of particle 1, m₁ = 2.58 g = 0.00258 kg

Speed of particle 1, v₁ = 2.51 m/s

Mass of particle 2, m₂ = 6.53 g = 0.00653 kg

Speed of particle 2 = 0 (at rest)

To find,

The speed of centre of mass of the two particles.

Solution,

The formula for the centre of mass of the system is givn by :

So, the speed of the centre of mass is 0.71 m/s.

hèllo, sorry i really need some more points so if you need this qustion answered than retype it

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6