What is momentum of 1.5 kg boulder dropped from a cliff after 3.0 s

Given :

Mass of object, m = 1.5 kg.

To Find :

The momentum of boulder dropped from a cliff after 3 seconds.

Solution :

Speed of boulder after 3 seconds of free fall is given by :

v = u + gt       ( Equation of motion )

v = 0 + 10×3    ( g = acceleration due to gravity )

v = 30 m/s

Now, momentum is given by :

P = m × v

P = 1.5 kg × 30 m/s

P = 45 kg m/s

Therefore, momentum of boulder is 45 kg m/s.