7. An outfielder throws a baseball to the first baseman at a speed of 19.6 m/s and an angle of 30° above the horizontal. If the ball in the described

situation is caught at the same height from which it was thrown, calculate

the amount of time the ball was in the air. (use -9.8 m/s2 for g in this

problem] [include the numerical answer and correct unit] *

The amount of time that the ball took in air is 1 second.

We must recall that the ball was thrown as a projectile and its time of flight must be obtained from the formula for the time of flight of a projectile as follows;

T = 2usinθ/g

u = initial velocity = 19.6  m/s

θ =  angle of projection = 30°

g = acceleration due to gravity = 9.8 m/s2

Substituting values;

T = 2 ×  19.6  m/s sin (30°)/9.8 m/s2

T = 1 second

Learn more about projectile: link

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