i hang a 15 cm length spring in the classroom. the spring has a spring constant of 99 N/m. i the. attach a mass of 439 g to the spring. based on the information provided, use hookes law to predict the new length of the spring. (answer in cm)

0.19 m

Explanation:

Spring constant (k) = 99 N/m

Length of spring hung = 15cm = 0.15m

Mass attached to the spring = 498g

The new length of spring :

F = kdx

F = mass (m) * acceleration due to gravity (g)

g = 9.8 m/s²

dx = L2 - L1 (Change in length)

m = 439 / 1000 = 0.439kg

L2 = new length

L1 = initial length

mg = k(L2 - L1)

0.439 * 9.8 = 99(L2 - 0.15)

4.3022 = 99(L2 - 0.15)

4.3022 = 99L2 - 14.85

4.3022 + 14.85 = 99L2

19.1522 = 99L2

L2 = 19.1522 / 99

L2 = 0.1934565

L2 = 0.19 m

New length of spring = 0.19 m

answer: option c.

explanation: