a ball kicked with a velocity of 8m/s at an angle of 30 degree to horizontal. calculate the time of flight of the ball. (g=10ms^2)

Approximately (assuming that air resistance is negligible.)

Explanation:

Let denote the initial velocity of this ball. Let denote the angle of elevation of that velocity.

The initial velocity of this ball could be decomposed into two parts:

If air resistance on this ball is negligible, alone would be sufficient for finding the time of flight of this ball.

Calculate given that and :

.

Assume that air resistance on this ball is zero. Right before the ball hits the ground, the vertical velocity of this ball would be exactly the opposite of the value when the ball was launched.

Since , the vertical velocity of this ball right before landing would be .

Calculate the change to the vertical velocity of this ball:

.

In other words, the vertical velocity of this ball should have change by during the entire flight (from the launch to the landing.)

The question states that the gravitational field strength on this ball is . In other words, the (vertical) downward gravitational pull on this ball could change the vertical velocity of the ball by each second. What fraction of a second would it take to change the vertical velocity of this ball by ?

.

In other words, it would take to change the velocity of this ball from the initial velocity at launch to the final velocity at landing. Therefore, the time of the flight of this ball would be .

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.

well clustered together.

points close on a scatter diagram