6. A 50 N block is raised 2 m. If the net work done on the block is 50 J, what is the applied force on the block?

The force applied in raising the block to the given height is 25 N.

The given parameters:

The force applied in raising the block to the given height is calculated as follows;

Thus, the force applied in raising the block to the given height is 25 N.

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F = 75[J]

Explanation:

We know that work is defined as the product of force by distance.

In this way we have two forces, the weight of the block down, and the force that bring about the block to rise.

where:

W = work = 50 [J]

d = distance = 2 [m]

Fweight = 50 [N]

Fupward [N]

Now replacing:

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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