Suppose you push a hockey puck of mass m across frictionless ice for a time δt, starting from rest, giving the puck speed v after traveling distance d. if you repeat the experiment with a puck of mass 2m, how long will you have to push for the puck to reach the same speed v?

Twice the previous time would be taken to reach the same speed v with the puck of mass 2m.

Explanation:

Let a Force pushes the hockey puck of mass m.

Then acceleration,

From the equation of motion,

......(1)

In the second case, when mass is 2m, then acceleration,

and t' is the time taken.

The final speed is v,

using equation (1)

Hence, it would take two times the previous amount of time to push the pluck of double mass.

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this