The heat vaporization for methyl alcohol is 1100 kj/kg. It is 2257 KJ/Kg for water. Thus means that. A) these are the amounts of energy to change temperature 1 degree C. required for these substances

B) Methyl alcohol requires less than half as much energy per kg to evaporate than water doe

C) water will get twice as ot as methyl alcohol during vaporization.

d) when alcohol and water evaporate they release 2,2 kj and 2257 kj of energy for every kg respectivly

Please hurry! I'm being timed!

B) Methyl alcohol requires less than half as much energy per kg to evaporate than water does

Explanation:

Latent heat of vaporization is the amount of heat required to convert 1 kilo gram of liquid into its vapor state without change in its temperature.

Heat of vaporization is more for water than for methyl alcohol which means more heat is required to convert from liquid to vapour form.

As the Heat of vaporization for methyl alcohol  (1100) is almost half as that of Heat of vaporization for water (2257) , it means  Methyl alcohol requires less than half as much energy per kg to evaporate than water does.

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