An engineer is designing a runway for an airport. Of the planes that will use this airport, the lowest acceleration rate is likely to be 4 m/s^2. The
takeoff speed of this plane will be 80 m/s. Assuming this is the minimum
acceleration, what is the minimum allowed length for the runway? (vf^2 =
vi^2 + 2a(df-di)) *

704m

Explanation:

Given, initial velocity, u=0m/s and final velocity v=65m/s

Acceleration a=3m/s 2

If d be the allowed length for the runway.

Using formula v*2 −u*2 =2aS

(65)*2−0*2 =2(3)d

⟹ d=65*2 /6=704.16∼704m

it's when something is going so fast it makes a loud noise, breaking the sound barrier, for example: a jet makes a loud noise, not only cause of the jet but because they reached a point where they went so fast that you can year the noise from various parts, kinda like a police car, lets say the car was going   so fast that you hear the siren of the cop car right next to you, but the car is probably a mile a way, it's cos the siren was next to you a few seconds if you understand me