An RLC parallel circuit has an applied voltage of 240 volts. R= 60 ohms, XL = 20 ohms, and Xc =36 ohms. What is the capacitor current?

6.67A

Explanation:

The voltage across the capacitor formula is expressed as;

VL = IXL

VL is the voltage across the capacitor = 240volts (since it is a parallel connection, all the elements will have the same voltage)

I is the capacitor current

XL is the capacitive reactance = 36 ohms

Recall from the formula:

VL = IXL

I = VL/XL

I = 240/36

I = 6.67A

Hence the capacitor current is 6.67A

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s