A dragster finishes a race with a speed of 50 meters per second. The driver deploys a drag chute which slows the car at a rate of -15 meters per second2.
Calculate the stopping distance of the dragster if only the drag chute is used
bring it to rest.

83.3m

Explanation:

From the question we are given the following:

initial speed u = 50m/s

acceleration a = -15m/s²

final speed = 0m/s

Required

Stopping distance S

Using the equation of motion:

0² = 50²+2(-15)S

0² = 2500 - 30S

-2500 = -30S

S = 2500/30

S = 83.3m

Hence the stopping distance of the dragster if only the drag chute is used  bring it to rest is 83.3m

what is the speed of a softball that travels 20m in 2secs

speed = 20/2 = 10 m/s