Show that a 2,500,000-J change in kinetic energy occurs for an airplane that is moved 500 m in takeoff by a sustained force of 5000 N.

The answer to your question is given below

Explanation:

To solve this problem, we'll assume that the plane is initially at rest.

Hence, the kinetic energy of the plane at rest is zero i.e Initial kinetic energy (KE₁) = 0

Next, we shall determine the final kinetic energy of the plan when the force was applied. This can be obtained as follow:

Force (F) = 5000 N

Distance (s) = 500 m

Energy (E) =?

E = F × s

E = 5000 × 500

E = 2500000 J

Since energy an kinetic energy has the same unit of measurement, thus, the final kinetic energy (KE₂) of the plane is 2500000 J

Finally, we shall determine the change in the kinetic energy of the plane. This can be obtained as follow:

Initial kinetic energy (KE₁) = 0

Final kinetic energy (KE₂) = 2500000 J

Change in kinetic energy (ΔKE) =?

ΔKE = KE₂ – KE₁

ΔKE = 2500000 – 0

ΔKE = 2500000 J

Hence, the change in the kinetic energy of the plane is 2500000 J.

increasing transnational kinetic energy. because the transnational kinetic energy formula consists of only two variables, mass and velocity, increasing one of those properties is the only way to increase an object's transnational kinetic energy. increases to mass and velocity, however, do not have the same impact.