1. A 146 kg cubic tiger began with an initial velocity of -22 m/s [N] and, while moving away from the origin, accelerated at -0.43 m/s² [N] and moved -407 m [N]. What was the final velocity of the tiger?

v = 28.87 m/s

Explanation:

Given that,

Mass of a cubic tiger, m = 146 kg

Initial velocity, u = -22 m/s

Acceleration, a = -0.43 m/s²

Distance moved, s = -407 m

We need to find the final velocity of the tiger. Using third equation of motion to find it. Let v is the final velocity of the tiger.

So, the final velocity of the tiger is 28.87 m/s.

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle