In a cylindrical water tube of length 4 cm and radius 6 mm, at t=0 s, the concentration of
mole
molecules of oxygen changes from 0.5
m3
mole
to 0.1
across the tube.
If the diffusion constant of oxygen inside water
is 8x 10-10 m2
find:
S
The number of mole of oxygen going from the
higher concentration to the lower concentration
every second
n =
v mole

In a cylindrical water tube of length 4 cm and

radius 6 mm, at t=0 s, the concentration of

mole

molecules of oxygen changes from 0.5

m3

mole

to 0.1

across the tube.

If the diffusion constant of oxygen inside water

is 8x 10-10 m2

find:

S

The number of mole of oxygen going from the

higher concentration to the lower concentration

every second

n =

v mole

the answer is 12 as i may remember

: )

it's a b and