A ball is released out a window that is 13 m above the ground. How fast will the ball be traveling when it reaches the ground? A. 32 m/s

B. 0.26 km/s

C. 0 m/s

D. 16 m/s

Option D. 16 m/s

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Height (h) = 13 m

Acceleration due to gravity (g) = 9.8 m/s²

Final velocity (v) =?

We can determine how fast (i.e final velocity) the ball is traveling when it reaches the ground as illustrated below:

v² = u² – 2gh

v² = 0² – (2 × 9.8 × 13)

v² = 0 – 254.8

v² = 254.8

Take the square root of both side.

v = √254.8

v = 15.96

v ≈ 16 m/s

Thus, the ball is travelling with a velocity of 16 m/s when it reaches the ground

answer: decibel

explanation: