A ball is thrown vertically upward with a speed v. An identical second ball is thrown upward with a speed of 1/2 v (half as fast). What is the ratio of the maximum height of the second ball to that of the first ball

1:4

Explanation:

The formula for calculating the maximum height of the ball is expressed as;

H = u²sin²theta/2g

If a ball is thrown vertically upward with a speed v, its maximum height is expressed as;

H = v²sin²90/2g

Since sin90 = 1

H = v²/2g 1

If an identical second ball is thrown upward with a speed of 1/2 v, then the maximum height will be expressed as;

H1 = (1/2v)²sin²90/2g

H1 = (v²/4)(1)/2g

H1 = v²/8g 2

Divide both equations

H/H1 = (v²/2g)/(v²/8g)

H/H1 = v²/2g × 8g/v²

H/H1 = 8g/2g

H/H1 = 4

Reciprocate both sides

H1/H = 1/4

H1:H = 1:4

Hence the ratio of the maximum height of the second ball to that of the first ball is 1:4

  the unit of the measure =

explanation:

  the property that is quantified by the energy needed per of material to raise the temperature by one.

  si unit of energy = joule (j)

  si unit of temperature = kelvin (k)

  si unit of mass of material = kilogram (kg)

the property that is quantified by the energy needed per of material to raise the temperature by one is called specific heat.

the unit of specific heat is

the journeys of marquette, joliet and la salle a) new france expand.

all three of these explorers explored the midwest and the area around the great lakes, which they subsequently claimed for france.

this was a big portion of territory and expanded new france which before then only consisted of quebec province in northeastern canada