A pool ball moving 1.33 m/s strikes an identical ball at rest. Afterward, the first ball moves 0.814 m/s at a 33.3° angle. What is the x-component and y-component of the velocity of the second ball? pls help quick

X - component = v2 = 0.650 m/s

Y - component = v2 = 0.447 m/s

Explanation:

Given that :

Conservation of momentum

m1u1 + m2u2 = m1v1 + m2v2

m = mass of pool ball ; u = initial velocity ; v = final velocity

Since the masses are identical

x - component

u1 + u2 = v1 + v2

u1 = 1.33 m/s

u2 = 0

Final speed of first ball = 0.814 m/s at an angle of 33.3° ;

v1 = 0.814*cos33.3 = 0.814 * 0.8358073 = 0.6803471 m/s

v2x = u1x + u2x - v1

v2x = 1.33 + 0 - 0.6803471

v2x = 0.6496529 m/s

v2x = 0.650 m/s

Y - component :

v1sinθ= 0.814*sin33.3 ; 0.814 * 0.5490228 = 0.4469045 m/s

v2y = 0.447 m/s

b) returns freshwater to the earth.

c) returns freshwater to the earth.c) occurs after condensation.

d) returns freshwater to the earth.c) occurs after condensation.d) roughly equal to the amount of evaporation.

happy to

pls mark as brainliest.

i dont know but

explanation:

whoever your teacher is, deserves a raise for using pokemon as an example