The vertical force f acts downward at A on the two membered frames. Determine the magnitude of the two components of F directed along axes of AB and AC. Set F=500N

The magnitude will be "353.5 N". A further solution is given below.

Explanation:

The given values is:

F = 500 N

According to the question,

In ΔABC,

⇒

⇒            

then,

⇒

⇒            

Now,

The corresponding angle will be:

⇒

⇒

⇒            

Aspect of F across the AC arm will be:

=

On putting the values of F, we get

=

=

Component F along the AC (in magnitude) will be:

=

=

=

(75°f − 32) × 5/9 = 23.889°c