Two points A=(+16) and B=(-4) At electric potential respectively find: a)which points is at higher potential?

b)what is the pontial difference b/w the two points?

c)the work done in moving acharge of 5C from A to B?

a. Point A

b. 20 V

c. 100 J

Explanation:

a. Point A is at a higher potential because there is a positive sign in front of its magnitude. Since it is a positive integral value, and has a higher magnitude than point B which is at -4, point A is thus at a higher potential than point B.

b. The potential difference between the two points ΔV = A - B

= +16 V - (-4 V)

= +16 V + 4 V

= + 20 V

c. The work done, W in moving a charge Q across a potential difference ΔV is W = QΔV

So, since Q = 5 C and ΔV = + 20 V  

W = QΔV

= 5 C × (+ 20 V)

= 100 J

- measure reactants precisely. ( first choice)

- stir to the reaction take place. ( second choice)

- wait patiently until the reaction completes. ( fourth choice)

- make sure to recover as much copper as possible. ( last choice)