A rightward-moving dragster accelerates from 0 m/s to 75 m/s in 4.5 s. Determine the magnitude of the average acceleration of the dragster in m/s/a
337.5 m/s/s
-16.67 m/s/s
28.5 m/s/s
-337.5 m/s/s
16.67 m/s/s
-28.5 m/s/s

The magnitude of the average acceleration of the dragster is 16.67

Explanation:

Acceleration is a vector quantity that relates changes in velocity to the time it takes to occur.

The average acceleration of a mobile is calculated using the following expression:

In this way you calculate the average change in speed in the desired time interval.

The unit of measurement in the International System of acceleration is the meter per second squared (m/s²)

In this case:

Replacing:

Solving:

acceleration= 16.67

The magnitude of the average acceleration of the dragster is 16.67

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.