Physics, 19.12.2020 14:00 minerrage43

A .183 kg ball is moving 18.8 m/s when it runs into a spring of spring constant 86.9 N/m. How much KE does the ball have when it has compressed the spring 0.520 m? (Unit=J)

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Answer from: lisagrimmett3

The value is $KE_B = 20.59 \ J$

Explanation:

From the question we are told that

The mass of the ball is $m = 183 \ kg$

The initial speed of the ball is $u = 18.8 \ m/s$

The spring constant is $k = 86.9 \ N/m$

The compression distance is $x = 0.520 \ m$

Generally the energy stored in the string is mathematically represented as

$E = \frac{1}{2} * k * x^2$

=> $E = \frac{1}{2} * 86.9 * 0.520 ^2$

=> $E = 11.75 \ J$

Generally the kinetic energy of the ball is mathematically represented as

$KE_b = \frac{1}{2} * m * u^2$

=> $KE_b = \frac{1}{2} * 0.183 * (18.8 )^2$

$KE_b = 32.34 \ J$

Generally the KE the ball have when it has compressed the spring is mathematically represented as

KE_B = KE_b - E

=> KE_B = 32.34 - 11.75

=> $KE_B = 20.59 \ J$

Answer from: Quest

i think it would be 80 km/h because 30 + 50 = 80 (sorry if this not the right answer i'm trying my best)

Answer from: Quest

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A .183 kg ball is moving 18.8 m/s when it runs into a spring of spring constant 86.9 N/m. How much K...

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