An object, initially moving in the negative X direction, is subject to a change in velocity in the positive Y direction. If the resulting velocity vector is drawn from the origin, which quadrant does this vector point to?

answer: a. same unit

explanation:

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j