The solar energy strikes the deck at the rate of 1400 W on every square metre. The steel plate of the deck is 0.010 m thick.
Steel has a density of 7800 kg / m³ and a specific heat capacity of 450 J / (kg °C).
13% of the solar energy striking the deck is absorbed and the rest is reflected.
Using these figures, calculate
1. how many joules of solar energy are absorbed by 1.0 m² of the deck in 1.0 s,
number of joules

Newton's law of cooling states that the rate of change in the temperature t(t) of a body is proportional to the difference between the temperature of the medium m(t) and the temperature of the body. that is, startfraction dt over dt endfraction equals upper k left bracket upper m left parenthesis t right parenthesis minus upper t left parenthesis t right parenthesis right bracket , where k is a constant. let kequals0.04 left parenthesis min right parenthesis superscript negative 1 and the temperature of the medium be constant, m(t) font size decreased by 3 equivalent font size decreased by 3 294 kelvins. if the body is initially at 369 kelvins, use euler's method with hequals0.1 min to approximate the temperature of the body after (a) 30 minutes and (b) 60 minutes.