What is the resistance of a wire with "p" of .25, a length "L" of 11.2, and an area "A" of 1.26?

Resistance = 2.2 Ohms.

Explanation:

Given the following data;

Resistivity, P = 0.25

Length, L = 11.2

Area, A = 1.26

To find the resistance.

Resistance is given by the formula below;

Resistance = PL/A

Substituting into the equation, we have;

Resistance = (0.25*11.2)1.26

Resistance = 2.8/1.26

Resistance = 2.2 Ohms.

Therefore, the resistance of the wire is 2.2 Ohms.

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

6 cos 34, 6 sin 34 trig