A -0.6 C charge that moves downward is in a uniform electric field with a strength of 200 N/C what is the magnitude and direction of the force on the charge

The magnitude and direction of the force on the charge is 120 N in the direction of the charge.

Explanation:

Given;

magnitude of the charge, q = 0.6 C

electric field strength, E = 200 N/C

The magnitude of the electric force is calculated as;

F = Eq

where;

F is the magnitude of the force

Substitute the given values and solve for F;

F = (200)(0.6)

F = 120 N in the direction of the charge.

Therefore, the magnitude and direction of the force on the charge is 120 N in the direction of the charge.

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