Which requires more work: lifting a 70 kg sack vertically 2 m or lifting a 35 kg sack vertically 4 meters?

they require the same amount of work

Explanation:

the formula for work is

W=Fnet*Displacement

and Fnet =m*a

a=9.81 m/s^2

Which gives us

W=ma*d

The set up would be;

(35kg*9.81m/s^2)*4 m=W

(70kg*9.81m/s^2)*2m=W

W= 1373.4 J

Both are the same therefore the correcr answer is *both require the same amount of work*

a=d/t

a="triangle"v/t

explanation:

a = acceleration