A horizontal wire PQ is perpendicular to a uniform horizontal magnetic field. A length of 0.25 m of the wire is subject to a magnetic field strength of 40 mT. A downward magnetic force of 60 mN acts on the wire. What is the magnitude and direction of the current in the wire

Complete question:

Please find the image uploaded for the diagram.

The magnitude of the current is 6 A, in the direction of Q to P.

Explanation:

Given;

length of the wire, l = 0.25 m

magnetic field strength, B = 40 mT = 0.04 T

Magnitude of the magnetic force, F = 60 mN = 0.06 N

The magnitude of the current in the conductor is given as;

F = BIL

Where;

I is the current induced in the conductor

I = F / BL

I = (0.06) / (0.04 x 0.25)

I = 6 A

Th current will move in direction of Q to P

the aurora is formed when charged particles emitted from the sun during a solar flare penetrate the earth's magnetic shield and collide with atoms and molecules in our atmosphere. these collisions result in countless little bursts of light, called photons, which make up the aurora.

auroras are generated by charged solar particles hitting molecules in earth's atmosphere. this usually happens in high latitudes, because our planet’s magnetic field tends to funnel these particles toward the poles. that’s why it can be experienced in northern ohio.