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1.78m/s

Explanation:

Given parameters:

Velocity of the arrow = 22.8m/s

Height of the wall  = 15.5m

Unknown:

Time taken for the arrow to reach the ground  = ?

Solution:

To solve this problem we employ the appropriate motion equation:

     H  = ut + g t²

 H  is the height

  u is the initial velocity = 0

   g is the acceleration due to gravity  = 9.8m/s²

  t is the unknown time

  15.5 = x 9.8 x t²

  15.5 = 4.9t²

     t² = 3.16

      t = 1.78m/s

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach

conservation of mass

mass before something happens = mass afterwards