4. A drag racing car's engine produces 12,000 Newtons of thrust, pushing the car forward down the track. Frictional forces resist the forward motion of the car witha total backward
force of 2010 Newtons. If the mass of the car is 820 kg, what is the acceleration of the
vehicle?

An 820 kg car that experiences a 12,000 N force forward and a 2,010 N force backward has an acceleration of 12.2 m/s².

A car experiences a 12,000 N force that pushes it forward and a 2,010 N force that pushes it backward. The net force (F) acting on the car is the difference between both forces.

An 820 kg (m) car experiences a net force (F) of 9,990 N. We can calculate the acceleration (a) of the vehicle using Newton's second law of motion.

An 820 kg car that experiences a 12,000 N force forward and a 2,010 N force backward has an acceleration of 12.2 m/s².

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Acceleration, a = 12.18 m/s²

Explanation:

Given the following data;

Forward force = 12000N

Backward force = 2010N

Mass = 820kg

First of all we would find the net force.

Since the forces are acting in opposite direction, we would subtract the values of the forces.

Net force, F = Forward force - Backward force

Net force, F = 12000 - 2010

Net force, F = 9990N

Now, to find the acceleration;

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

Where;

Making acceleration (a) the subject, we have;

Substituting into the equation;

Acceleration, a = 12.18 m/s²

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.