At a distance of 5.0 m from a point sound source, the sound intensity level is 110 dB. At what distance is the intensity level 95?

The distance of the second sound intensity level is 28.12 m.

Explanation:

Given;

intensity of first sound level, I₁ = 110 dB

distance of first sound level, r₁ = 5 m

intensity of second sound level, I₂ = 95 dB

let the distance of second sound level =  r₂

The intensity of the sound in W/m² is given as;

where;

I₀ is threshold of hearing = 1 x 10⁻¹² W/m²

for 110 dB to W/m²

for 95 dB to W/m²

The intensity of sound is related to distance as follows;

Now, determine the distance of the second sound intensity level

Therefore, the distance of the second sound intensity level is 28.12 m.

12000j is work done