522 J of work are done on a system in a process that decreases the system's thermal energy by 240 J. How much heat energy is transferred to or from the system?

ΔQ = - 762 J (Negative Sign shows heat transfer from the system)

Explanation:

The heat transferred to or from the system can be given by using First law of Thermodynamics as follows:

where,

ΔQ = Heat Transferred to or from system = ?

ΔU = Change in Internal Energy of System = Change in Thermal Energy

ΔU = - 240 J (negative sign due to decrease in energy)

W = Work done on system = -522 J (negative sign due to work done "on" system)

Therefore,

ΔQ = - 762 J (Negative Sign shows heat transfer from the system)

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j