JUST TWO QUESTIONS PLEASE HELP IM SO LOST AND I HAVE TO SUBMIT ITTT

Sry,i only the answer of that question no.1

(m)=1000kg

(u)=30m/s

(f)=5000n

(v)=0m/s

(a)=f/m

= 5000/1000

=5

Distance(s)=?

We know that,

V^2=u^2+2as

Or,0^2=30^2+2×5×s

Or,s=910m

So,the minium distance required to stop the car is 910m.

Hope,itwillhelpya!

nah.   i'm just sleepy.

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.