X-rays in a dental X-ray machine are produced when an electron converts its kinetic energy into a photon. In one particular X-ray machine, an electron accelerates through a potential difference of 9.00 x 104 V to create a single photon. What is the frequency of the X-ray produced in this particular X-ray machine?

In a load, the load is paralel to the shaft. n a. angular n b. thrust n c radial n d. none of the above

Clara is shopping in a grocery store with her friend. each has their own shopping cart in which they want to place their items. the shopping carts are identical. clara and her friend add the same type and number of items to each of their carts. in the baking aisle, however, clara adds 20 pounds of sugar to her own cart, and her friend adds only 10 pounds of sugar to her own cart. which of the following statements best explains what clara must do to accelerate at the same rate as her friend? a. she must add more sugar to her cart. b. she must apply more force to move her cart. c. she must add 20 pounds of salt instead of 20 pounds of sugar to her cart. d. she must apply less force to move her cart.

Conceptualize notice how this problem differs from our previous discussion of gauss's law. the electric field due to point charges was discussed in the previous section. now we are considering the electric field due to a distribution of charge. we found the field for various distributions of charge in the chapter entitled electric fields by integrating over the distribution. this example demonstrates a difference from our discussions in the previous chapter. in this chapter, we find the electric field using law. categorize because the charge is distributed uniformly throughout the sphere, the charge distribution has spherical symmetry and we can apply gauss's law to find the field. analyze note that the following conditions can be used to determine a suitable gaussian surface. condition (1): the value of the electric field can be argued by symmetry to be constant over the portion of the surface. condition (2): the dot product e â· da can be expressed as a simple algebraic product e da because e and da are parallel.