A 1 kg puck sliding on a horizontal shuffleboard court is slowed to rest by 1 point a frictional force of 3 N. What is the coefficient of kinetic friction between
the puck and the surface of the shuffleboard court? *
O A. 0.25
O B.0.5
O c.0.15
D. .31

miu = 0.31

Explanation:

The friction force is defined as the product of the normal force by the coefficient of friction.

where:

f = friction force = 3 [N]

miu = friction coefficient

N = normal force [N]

The normal force on a horizontal surface can be calculated by means of the product of mass by gravity.

where:

m = mass = 1 [kg]

g = gravity acceleration = 9.81 [m/s²]

Now replacing in the equation above, we can find the friction coefficient.

b.

explanation:

10.0

the area between the graph and the t axis