A plane lands and comes to a complete stop. If the plane covers 200 m and decelerates at 7.5 m/s2 , what was the planes initial velocity as it touched the runway?

The initial velocity of the plane is 54.77 m/s

Explanation:

Given;

distance covered by the plane, d = 200 m

deceleration of the plane, a = - 7.5 m/s²

The initial velocity of the plane is given by the following kinematic equation;

v² = u² + 2ad

where;

v is the final velocity of the plane when the plane comes to a complete stop = 0

u is the initial velocity of the plane

0 = u² + 2(-7.5 x 200)

0 = u² - 3000

u² = 3000

u = √3000

u = 54.77 m/s

Therefore, the initial velocity of the plane is 54.77 m/s

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