Light of wavelength 400 nm falls on a metal surface having a work function 1.70 eV. What is the maximum kinetic energy of the photoelectrons emitted from the metal? a. 4.52 eV
b. 3.11 ev
c. 141 eV
d. 2.82 eV
e. 1.70 eV

Ke = 1.41 eV

Explanation:

We know that

h = 6.626 x 10⁻²⁴

c = 3 x 10⁸

λ = 4 x 10⁻⁹ x 1.6 x 10⁻¹⁹

Computation:

Ke = [hc / λ] - w

Ke = [(6.626 x 10⁻²⁴)(3 x 10⁸) / (4 x 10⁻⁹ x 1.6 x 10⁻¹⁹)] - 1.70

Ke = 1.41 eV

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

gravitational energy

electrical energy

kinetic energy

ligh energy