A submarine rests on the sea bottom. The normal force exerted upon the sub by the sea-floor is equal toA) the weight of the sub less the weight of the displaced water. B) the weight of the displaced water. C) the weight of the sub plus the weight of the displaced water. D) the buoyant force less 1 atmosphere acting on the sub. E) the weight of the sub.

answer: question1

1,000 tons

question2

3: 8

question 3

store d

step-by-step explanation:

yup its correct its: c) b b

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.

answera compound;