How much tension must a rope withstand if it is used to accelerate a 960 kg car horizontally along a frictionless track at 1.20 m/s²?

The tension of the rope is 1152 N

Explanation:

Force

Newton's second law states that the acceleration of an object is directly proportional to the net force and inversely related to its mass.

The law can be written as:

F = m.a

The rope must apply a force F to accelerate the car of m=960 Kg at . Given the track is frictionless, all the force applied produces acceleration, thus:

F = 1152 N

The tension of the rope is 1152 N

c)as speed changes, wavelength and frequency change.

everything changes!

float.

archimedes' principle

denser than water sinks in water.

denser than mercury would sink in it