If your problem 50 joules of work lifting a 10 - box from to a shelf how high is the segregation

5m

Explanation:

Given parameters:

Work done in lifting the box  = 50J

Force applied  = 10N

Unknown:

Height of lifting the box  = ?

Solution:

Work done is the produce of force and distance;

      Work done  = Force x distance

Now to find the height;

  Work done  = Force  x height;

   50  = 10 x h

         h  = 5m

t2 equal the displacement of the particle over the same time period if t2> t/2? hint: consider a sine wave starting at t1=0, then consider a closing wave starting at t1=0, for your explanatio

not moving. pos accel,