Una mujer sale de su casa, camina 650 m al Oeste y luego 500 m al Norte hasta llegar al centro comercial donde va a realizar sus compras. Calcular: a) distancia total recorrida y b) magnitud y dirección de su desplazamiento resultante.

Explanation:

De la información dada:

La distancia total recorrida= 650 m + 500 m

La distancia total recorrida= 1150 m

La magnitud se puede calcular utilizando el teorema de Pitágoras.

a² = b² + c²

a² = 500² + 650²

a² = 250000 + 422500

a² = 672500

a =

a = 820 m

La dirección del desplazamiento resultante es la dirección noreste desde el punto de partida.

the velocity you are looking for is made up of two parts: horizontally velocity, vh, and its vertical velocity, vv. the actual velocity of the ball will be these two parts added together, and because velocity is a vector then they will need to be added vectorially.  

neglecting air resistance etc etc.,  

the horizontal velocity component will be constant (because there is no accelerating force in the horizontal direction.  

vh = 8 ms-1  

the vertical velocity component has an accelerating force: 'g'.  

using v = u +at where a = g = 9.81 ms-2.  

the vertical component of velocity, vv = 0 + gt = vv =9.81 x 2  

vv = 19.62 ms-1 . the zero appears because the virtical component of velocity at time t=0 is zero. remember, the ball was thrown horizontally.  

how fast it will be moving (it actual path (being a parabola )) will be the vector sum of these two.  

adding vectorally gives: -  

v = sqr root (8^2 + 19.62^2) = sqr root(64+384.9) = 21.18 or 21.2 ms-1

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.