This diagram shows two different forces acting on a skateboarder. The combined mass of the skateboard and the person is 65.2 kg. Based on this
information, what is the acceleration of the skateboarder?
Air resistance = 55.20 N
Applied force = 31.80
si
A. 0.36 m/s2 to the left
B. 1.46 m/s2 to the left
C. 0.36 m/s2 to the right
D. 1.47m/s2 to the right

Option A. 0.36 m/s to the left

Explanation:

From the question given above, the following data were obtained:

Force resistance (Fᵣ) = 55.2 N

Applied force (Fₐ) = 31.8 N

Mass (m) = 65.2 kg.

Acceleration (a) =?

Next, we shall determine the net force acting on the skateboarder. This can be obtained as illustrated below:

Force resistance (Fᵣ) = 55.2 N

Applied force (Fₐ) = 31.8 N

Net force (Fₙ) =?

Fₙ = Fᵣ – Fₐ

Fₙ = 55.2 – 31.8

Fₙ = 23.4 N to the left

Finally, we shall determine the acceleration of the skateboarder. This can be obtained as follow:

Mass (m) = 65.2 kg.

Net force (Fₙ) = 23.4 N to the left

Acceleration (a) =?

F = ma

23.4 = 65.2 × a

Divide both side by 65.2

a = 23.4 / 65.2

a = 0.36 m/s

Since the net force acting on the skateboarder is to the left. Therefore, the acceleration of the stakeholder will also be towards the left (i.e 0.36 m/s to the left)