a 1.2kg spring-activated toy bomb slides on a smooth surface along the x-axis with a speed of .05m/s. A the origin 0, the bomb explodes into two fragments. Fragment 1 has a mass of .40kg and a speed of .90m/s along the negative y-axis. Find the magnitude and direction of the velocity of fragment 2.

Explanation:

m = Mass of initial piece = 1.2 kg

= Velocity of toy in x direction = 0.05 m/s

= Velocity of toy in y direction = 0

= Velocity of fragment 1 in x direction = 0

= Velocity of fragment 1 in y direction = -0.9 m/s

= Velocity of fragment 2 in x direction

= Velocity of fragment 2 in y direction

= Mass of fragment 1 = 0.4 kg

= Mass of fragment 2 = 1.2-0.4 = 0.8 kg

Applying conservation of momentum in x axis

Applying conservation of momentum in y axis

From the above two final equations we get

The direction of the fragment 2 is

The velocity of fragment 2 is

cell differentiation  is how generic embryonic  cells  become specialized  cells. this occurs  through a process called gene expression. gene expression is the specific combination of genes that are turned on or off (expressed or repressed), and this is what dictates how a  cell  functions.

explanation:

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂