Use the dichotomous key shown below to identify the animal shown in the picture above. 1.a. Tail length is about half of leg length (or shorter) . go to 2. 1.b. Tail length is similar to or longer than leg length . go to 3. 2.a. Tail tip is solid black, and tail has no stripes; ear length and length of black hair tufts on ear tips are approximately equal . Canada lynx. 2.b. Tail tip is not solid black, and tail has stripes; length of black hair tufts on ear tips much shorter than ear length . bobcat. 3.a. Fur is fairly uniform in color (usually tan) and lacks spots . mountain lion. 3.b. Tan to reddish brown coat with black spots . ocelot. A. bobcat B. mountain lion C. ocelot D. Canada lynx

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

Iwould say the answer is d

What about pink because im not too fond of red