What is the magnitude of the change in potential energy of the block-spring system when it travels from its lowest vertical position to its highest vertical position?

Potential energy is defined as the energy stored in a body which may convert into kinetic energy when moved.

The Formule of the potential energy is The correct answer is 0

Hence,

 The H stated as the measured from the equilibrium point of the spring

Therefore, the potential energy at the maximum point is    and the potential energy at the minimum point is    

Hence, after solving it we got

Therefore, the energy change in the process is 0.

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 ΔU = 2 mg h

Explanation:

In a spring mass system the potential energy is U = m g h

where h is measured from the equilibrium point of the spring

the potential energy at the highest point is

         U₁ = m g h

the potential energy at the lowest point is

         U₂ = m g (-h)

instead in this energy it is

          ΔU = 2 mg h

In this two points the kinetic energy is zero, but there is elastic potential energy that has the same value in the two points, so its change is zero

e) none of the above answers are correct

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2