A car drives 0.696 km North, and then turns and drives 4.326 km East. Calculate the magnitude of the car's resultant displacement. Include equation, substitution with units, and answer with units.

4.3186km

Explanation:

If a car drives 0.696 km North, and then turns and drives 4.326 km East, the magnitude of the car's resultant displacement will be gotten using the Pythagoras theorem as shown;

d² = x²+y²

Given;

x = 4.326km

y = 0.696km

Substitute into the formula and get d;

d² = (4.326)²+(0.696)²

d² = 18.714276+0.484416

d² =19.198692

d = √19.198692

d = 4.3816km

Hence the magnitude of the car's resultant displacement is 4.3186km

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees. 

the force on the thing and the distance the force moves the thing