how would you find the displacement from t = 0.3 to t = 0.33 under this graph? would it be measured on the time axis?

Explanation:

from t = .3 to t = .33 , velocity appears to be uniform .

uniform velocity = .22 m /s

displacement will be area of the v-t graph which is a rectangle .

= .22 x ( .33 - .3 )

= .22 x .03

= 66 x 10⁻⁴ m

= 6.6 mm .

answera compound;

in order to follow the instructions and complete the statements, i need to use data from table c of your student guide. can you think of a way to let me see your student guide for a while ? i can't answer the question without the data in table c.