Physics, 10.11.2020 07:20 sierravick123owr441

A car of mass 1460 kg is on an icy driveway inclined at an angle of 33◦. The acceleration of gravity is 9.8 m/s^2. If the incline is frictionless, what is the acceleration of the car?Answer in units of m/s^2

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Answer from: cocothunder635

The acceleration of the car along the frictionless incline is 5.3374m/s

Since the acceleration of the car along the incline if the incline is frictionless is expressed as;

$a_y=asin\theta$

Given the following:

a = 9.8 m/s²

$\theta$ = 33 degrees

Substituting the given parameters into the formula;

$a_y=9.8sin33^0\\a_y=9.8(0.5446)\\a_y=5.3374m/s^2$

Hence the acceleration of the car along the frictionless incline is 5.3374m/s²

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Answer from: yvngtazz

5.3 m/s^2 (rounded)

Explanation:

I GOT YOU DAVID!

9.8 x sin(33) = 5.33746254 m/s^2

Answer from: Quest

diagram is missing, but i will try to explain your doubt.

answer:

amplitude is the maximum displacement or distance moved on a point of a vibrating body or wave measured from its equilibrium position.it is equal to half the length of vibration path.

Answer from: Quest

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

$_a^z\textrm{x}\rightarrow _{a-2}^{z-4}+_2^4\alpha$

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

$_a^z\textrm{x}+_{-1}^0\textrm{e}\rightarrow _{z-1}^a\textrm{y}$

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases $\gamma -radiations$ . this process does not change the mass number.

$_a^z\textrm{x}^*\rightarrow _a^z\textrm{x}+_0^0\gamma$

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as $\beta ^+$ -decay. in this the mass number remains same.

$_a^z\textrm{x}\rightarrow _{z-1}^a\textrm{y}+_{+1}^0e$

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

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