g A ring and solid sphere are rolling without slipping so that both have a kinetic energy of 126 J. What is the rotation kinetic energy of the ring

63J

Explanation:

The question tells us that they both have a kinetic energy of 126 J. What we are required to get is the rotation kinetic energy of the ring

Total kinetic energy =

1/2mv² + 1/2IW²

For ring,

I = mr²

And v = Rw for pure rolling

The total kinetic energy

= 1/2mr² + 1/2mv²

= 126J

126/2

= 63J

The rotational kinetic energy of the ring is therefore 63J.

Thank you!

kepler used the data from tycho blahe (his mentor) to construct the laws of planetary motion.