5. A beach ball, moving with a speed of 1.27 m/s, rolls off a pier and hits the water 0.75 m from the end of the pier.
a. How high is the pier above the water?
b. If the same beach ball moved off at 4.50 m/s, how far out from the end of the pier would it land?

A. 1.71 m

B. 2.66 m

Explanation:

A. Determination of the height of the pier.

We'll begin by calculating the time taken for the ball to get to the water

This can be obtained as follow:

Horizontal velocity (u) = 1.27 m/s,

Horizontal distance (s) = 0.75 m

Time (t) =?

s = ut

0.75 = 1.27 × t

Divide both side by 1.27

t = 0.75 / 1.27

t = 0.59 s

Finally, we shall determine the height of the pier as follow:

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) = 0.59 s

Height of pier (h) =?

h = ½gt²

h = ½ × 9.8 × 0.59²

h = 4.9 × 0.3481

h = 1.71 m

Thus, the height of the pier is 1.71 m

B. Determination of the horizontal distance.

Horizontal velocity (u) = 4.50 m/s

Time (t) = 0.59 s

Horizontal distance (s) =?

s = ut

s = 4.5 × 0.59

s = 2.66 m

Thus, if the ball moved at a velocity of 4.50 m/s off the pier, it will land at a distance of 2.66 m from the end of the pier.

the independent variable, the one that is intentionally manipulated, is whether or not the car hits the barrier.

the dependent variable, the one that you measure the response in, is the distance that the washers travel.

momentum of soft ball three times less than baskey ball