Vitellium (Vi) has the following composition: Vi–188: 187.9122 amu; 10.861%
Vi–191: 190.9047 amu; 12.428%
Vi–193: 192.8938 amu; 76.711%
Based on this data, what can you predict about the average atomic mass of vitellium?

A . It will be equal to the arithmetic mean of the masses of the three isotopes.

B . It will be closer to the mass of Vi–188.

C It will be closer to the mass of Vi–193.

D . It will be equal to the mass of Vi–193.

C It will be closer to the mass of Vi–193.

Explanation:

The average atomic mass of vitellium will be closer to the mass of Vi–193.

From the geonormal abundance we can derive the average atomic mass or relative atomic mass of the compound.

 Average atomic mass = sum of all the product of the mass of isotope x abundance of isotope

Average atomic mass = (10.861% x 187.9122) + (12.428% x 190.9047) + (76.11% x 192.8938)

 Average atomic mass  = 20.41 + 23.73 + 146.81  = 190.95amu

5 w for 1hr = 5x60x60 joules=300x60=3000x6=18,000j as total energy conversion. efficiency of bulb needed for radiant to thermal within 18000